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If f(k)=1∫−1√1−x2√k+1−xdx, then the value of 99∑k=0f(k) is (Take π=3.14) |
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Answer» If f(k)=1∫−1√1−x2√k+1−xdx, then the value of 99∑k=0f(k) is (Take π=3.14) |
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