InterviewSolution
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InterviewSolution
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If `f(m) = sum_(i=0)_(m) ({:(30),(30-i):})({:(20),(m-i):})` where `({:(p),(q):})= ""^(p)C_(q)`, thenA. maximum value of `f(m)` is `.^(50)C_(25)`B. `f(0) + f(1)+"….."+f(50) = 2^(50)`C. `f(m)` is always divisible by `50(1 le m le 49)`D. The value of `underset(m=0)overset(50)sum(f(m))^(2) = .^(100)C_(50)` |
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Answer» Correct Answer - A::B::D `f(m)= underset(i=0)overset(m)sum({:(" "30 ),(30-i):})({:(" "30 ),(m-i):})= underset(i=0)overset(m)sum({:(" "30 ),(" "i):})({:(" "20 ),(m-i):})= .^(50)C_(m)` `f(m)` is greatest when `m = 25`. Also, `f(0)+f(1)+"….." +f(50)= .^(50)C_(0) + .^(50)C_(1)+.^(50)C_(2)+"....."+.^(50)C_(50) = 2^(50)` Also, `.^(50)C_(m)`is not divisible by 50 for all m as 50 is not a prime number `underset(m=0)overset(50)sum(f(m))^(2)=(.^(50)C_(0))^(2)+(.^(50)C_(1))^(2)+(.^(50)C_(2))^(2)+"......."+(.^(50)C_(50))^(2)` `= .^(100)C_(50)` |
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