1.

If \(f(n) =\begin{cases}\frac{x^2 - 4}{x - 2},\,x \neq 2 \\k,x=2\end{cases}\) is continuous at x = 2, then k =f(n) = {(x2 - 4)/(x - 2), x ≠ 2, k, x = 2 is continuous at x = 2, then k =(a) 2 (b) 4 (c) 6 (d) 3

Answer»

Correct answer is

(b) 4



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