Saved Bookmarks
| 1. |
If \(f(n) =\begin{cases}\frac{x^2 - 4}{x - 2},\,x \neq 2 \\k,x=2\end{cases}\) is continuous at x = 2, then k =f(n) = {(x2 - 4)/(x - 2), x ≠ 2, k, x = 2 is continuous at x = 2, then k =(a) 2 (b) 4 (c) 6 (d) 3 |
|
Answer» Correct answer is (b) 4 |
|