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If f : R → R, g : R → R are defined by f(x) = 3x – 1, g(x) = x2 + 1, then find fog(2). |
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Answer» Given f(x) = 3x –1 and g(x) = x2 +1 (fog) (2) = f [g (2)] = f [22 + 1] = f (5) = 3 (5) – 1 = 14 ∴ (fog) (2) = 14 |
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