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If f:R→R is invertible function such that ∫f(x)dx=g(x),then ∫f−1(x)dx is equal to (assuming c as arbitrary constant) |
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Answer» If f:R→R is invertible function such that ∫f(x)dx=g(x),then ∫f−1(x)dx is equal to (assuming c as arbitrary constant) |
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