If f(t)=⎡⎢⎣cos tt12 sin tt2tsin ttt⎤⎥⎦, then limt→0f(t)t

1.	If f(t)=⎡⎢⎣cos tt12 sin tt2tsin ttt⎤⎥⎦, then limt→0f(t)t2 is equal to (a) 0 (b) -1 (c) 2 (d) 3
Answer» If $f (t) = ⎡ ⎢ ⎣ \begin{matrix} c o s t & t & 1 2 s i n t & t & 2 t s i n t & t & t \end{matrix} ⎤ ⎥ ⎦$ , then $l i m t \to 0 \frac{f (t)}{t^{2}}$ is equal to (a) 0 (b) -1 (c) 2 (d) 3

If f(t)=⎡⎢⎣cos tt12 sin tt2tsin ttt⎤⎥⎦, then limt→0f(t)t2 is equal to (a) 0 (b) -1 (c) 2 (d) 3

Answer»

If $f (t) = ⎡ ⎢ ⎣ \begin{matrix} c o s t & t & 1 2 s i n t & t & 2 t s i n t & t & t \end{matrix} ⎤ ⎥ ⎦$ , then $l i m t \to 0 \frac{f (t)}{t^{2}}$ is equal to

(a) 0
(b) -1
(c) 2
(d) 3

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If f(t)=⎡⎢⎣cos tt12 sin tt2tsin ttt⎤⎥⎦, then limt→0f(t)t2 is equal to (a) 0 (b) -1 (c) 2 (d) 3

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