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If f(x)=|1−x|, then the number of points (excluding the boundary points if exist) where g(x)=sin−1(f(|x|)) is non-differentiable, is |
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Answer» If f(x)=|1−x|, then the number of points (excluding the boundary points if exist) where g(x)=sin−1(f(|x|)) is non-differentiable, is |
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