1.

If f(x) = (3x+2)^100 and f ' (x) = n(3x+2)^99 then what is the value of n ?

Answer»

SOLUTION :`F(x)=100(3x+2)^100rArrf(x)=100(3x+2)^99 3=n(3x+2)^99(GIVEN)thereforen=300`


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