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If f(x) = .^(40)C_(1).x(1-x)^(39) + 2..^(40)C_(2)x^(2)(1-x)^(38)+3..^(40)C_(3)x^(3)(1-x)^(37)+"….."+40..^(40)C_(40)x^(40), then the value of f(3) is |
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Answer» 120 `T_(r)=r..^(40)C_(r).x^(r)(1-x)^(40-r)` `= 40x..^(39)C_(r-1).x^(r-1)(1-x)^(40-r)` `:. f(x)=40x(x+1-x)^(39)` `= 40x` |
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