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If f(x)=((7x+1)sinx)/(e^(x)logx) " and "f^(')(x)=f(x)g(x), then g^(')(x)= |
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Answer» `1/(x^(2)logx)+1/(XLOGX)^(2)-cosec^(2)x-49/(7x+1)^(2)` |
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