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If `f(x)=cos[pi^(2)]x+cos[-pi^(2)]x`, where `[x]` stands for the greatest integer function, thenA. `f ((pi)/(2))= -1`B. `f(pi)=1`C. `f(-pi)=0`D. `f((pi)/(4))= (-1)/(sqrt(2))` |
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Answer» Correct Answer - A::C::D Let `f(x) = cos` ………….. `2pi^(2)=19.72` `3pi^(2)=29.58` `:. [2pi^(2)]=19, [-3pi^(2)]= -30` `f ((pi)/(2))= -1 , f(pi) = 0 , f(-pi) = 0 , f ((pi)/(4)) = (-1)/(sqrt(2))` |
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