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If f(x)=e^{2x} and g(x)=\log\sqrt x(x>0), then fog(x) is equal to (1) e^{2x} (2) \log\sqrt x (3) e^{2x}(\log\sqrt x) (4) x |
| Answer» If f(x)=e^{2x} and g(x)=\log\sqrt x(x>0), then fog(x) is equal to (1) e^{2x} (2) \log\sqrt x (3) e^{2x}(\log\sqrt x) (4) x | |