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If f(x) = `e^(x)`, then `lim_(xto0) (f(x))^((1)/({f(x)}))` (where { } denotes the fractional part of x) is equal to -A. f (1)B. f (0)C. f (-`oo`)D. Does not exist |
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Answer» Correct Answer - D `{c^(x)}=[{:(e^(x)-1",",xgt0^(+)),(e^(x)",",xlt0^(-)):}` `underset(xto0^(-))(lim)(e^(x))^((1)/(e^(x)))=1` `underset(xto0^(+))(lim)(e^(x))^((1)/(e^(x)-1))=e` `rArr` limit does not exist at x = 0 |
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