1.

If f(x) is a polynomial such that (alpha+1)f(alpha)-alpha=0AA alpha epsilon Nuu{0}, alpha le n, then

Answer»

`f(76)` is 1
`f(21)` is `10/11`
`f(37)` is `1/7`
`f(148)` is `9/13`

Solution :`G(X)=(x+1)f(x)-xs`
`g(x)=0` for `x=0,1,2,……..n`
`g(x)=ax(x-1)…….(x-n)`
`:. (f(x)=((-1)^(n+1)x.(x-1)…..(x-n))/(|___(n+1))+x)/(x+1`


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