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If `f(x)` is a polynomial such that `(alpha+1)f(alpha)-alpha=0AA alpha epsilon Nuu{0}, alpha le n`, thenA. `f(76)` is 1B. `f(21)` is `10/11`C. `f(37)` is `1/7`D. `f(148)` is `9/13` |
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Answer» Correct Answer - A::B `g(x)=(x+1)f(x)-xs` `g(x)=0` for `x=0,1,2,……..n` `g(x)=ax(x-1)…….(x-n)` `:. (f(x)=((-1)^(n+1)x.(x-1)…..(x-n))/(|___(n+1))+x)/(x+1` |
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