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If f(x) is invertible and twice differentiable function satisfying f′(x)=f(x)∫0f−1(t)dt,∀ xϵR and f′(0)=1, then f′(1)=ea/4 where value of a is

Answer» If f(x) is invertible and twice differentiable function satisfying f(x)=f(x)0f1(t)dt, xϵR and f(0)=1, then f(1)=ea/4 where value of a is


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