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If f(x)=k^(3)x+k^(3)-2 cuts the curve g(x)=1/2Inx^(2) at exactly one point 'k' may lie in the interval |
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Answer» `(1/(SQRT(e)),e)` So, `F(x)=k^(3)+3"In"k-1` `f(1/sqrt(e))f(e)lt0`
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