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If f(x) = kx3 - 9x2+9x+3 is increasing for every real number x, thenA. k > 3B. k ≥ 3C. k < 3D. k ≤ 3 |
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Answer» Answer is : A. k > 3 Given f(x) = kx3 - 9x2+ 9x+3 ⇒ f’(x) = 3kx2 - 18x+9 ⇒ f’(x) = 3(kx2 – 6x + 3) > 0 ⇒ kx2 – 6x + 3 > 0 For quadratic equation to be greater than 0. a > 0 and D < 0 ⇒ k > 0 and (-6)2- 4(k)(3) < 0 ⇒ 36 – 12k < 0 ⇒ 12k > 36 ⇒ k > 3 ∴ k > 3. |
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