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If `f(x)=lim_(m->oo) lim_(n->oo)cos^(2m) n!pix` then the range of f(x) isA. `f(sqrt(3))=1`B. `f(3)=1`C. `f(sqrt(2))=0`D. `f(1)=2` |
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Answer» Correct Answer - B::C When `x=` rational then `cosn!pix=+-1` so `f(x)=1` When `x=` irrational then `cosn!pixepsilon(-1,0)uu(0,1)` `impliesf(x)=0` |
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