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If f(x)=log0.1(1−|x|1+|x|), then the number of integral values of x, satisfying f(x)≥f(x2) is |
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Answer» If f(x)=log0.1(1−|x|1+|x|), then the number of integral values of x, satisfying f(x)≥f(x2) is |
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