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| 1. |
If f'(x)=sqrt(2x^2-1) and y=f(x^2) then what is dy/dx at x = 1 ? |
| Answer» SOLUTION :`y=f(X^2)rArrdy/dx=f(x^2)2x=2xsqrt(2x^4-1)(thereforef(x)=SQRT(2x^2-1))thereforedy/dx]_(x=1)=2sqrt(2-1)=2 | |