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If f(x)=sum_(r=0)^(20) .^(20)C_(r) (In (1+x))^(r),g(x)=sum_(r=0)^(20)(-1)^(r).^(20)C_(r)(1+3sinx)^(20-r) then, |
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Answer» `sum_(r=0)^(oo)(G(pi//6))^(r)=(6^(20))/(2^(20)-1)` |
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