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If f(x)=tan−1(1−√x2−1√x2+2√x2−1)+sin−1(√x2−1|x|) for |x|≥1, then the number of solution(s) of the equation tan(f(x))=|x2−2| is |
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Answer» If f(x)=tan−1(1−√x2−1√x2+2√x2−1)+sin−1(√x2−1|x|) for |x|≥1, then the number of solution(s) of the equation tan(f(x))=|x2−2| is |
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