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If f(x)=x+1∫x−1e−(t−1)2 dt, then the maximum value of f(x) will occur at x equal to (correct answer + 2, wrong answer - 0.50) |
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Answer» If f(x)=x+1∫x−1e−(t−1)2 dt, then the maximum value of f(x) will occur at x equal to |
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