1.

If f(x)=||x-1|+|x-3|-|2x-1||+||x-1|+|x-3|+|2x-1||, then

Answer»

`F(X)` is non-differentiable at `x=1`
`f(x)` is non differentiable at `x=3/2`
`f(x)` has minimum value is 2
`x=1` is POINT of local minima

Solution :`:'f(x)=2XX"max"{|x-1|+|x-3|,|2x-1|}`
`:.x=1, 3/2` point of non-differentiability and minimum value is 2


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