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If `f(x)=x^2+x+3/4`and `g(x)=x^2+a x+1`be two real functions, then the range of `a`for which `g(f(x))=0`has no real solution is`(-oo,-2)`b. `(-2,2)`c. `(-2,oo)`d. `(2,oo)`A. `(-oo,-2)`B. `(-2,2)`C. `(-2,oo)`D. `(2,oo)` |
Answer» Correct Answer - C `f(x)=x^(2)+x+(3)/(4)=(x+(1)/(2))^(2)+(1)/(2)ge(1)/(2)` `g(f(x))=f(x)^(2)+af(x)+1` for g(f(x))=0, `a=-(f(x)+(1)/(f(x)))le-2` `therefore` If `a gt -2, g(f(x))=0` has no solutions |
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