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If ` f(x) = x^4 - 2 x^3 + 3 x^2 -ax +b` is a polynomial such that when it is divided by x-1 and x+1 the remainders are respectively 5 and 19. Determine the remainder when f(x) is divided by x-2. |
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Answer» `f(x)=x^4-2x^3+3x^2-ax+b` `f(1)=1-2(1)+3(1)-a+b` `b-a=3-(1)` `f(-1)=1-2(-1)+3(1)-a(-1)+b``19=1+2+3+a+b` `a+b=13-(2)` adding equation 1 and 2 `2b=16` `b=8` `a=8-3=5` f(2)=16-2*8+3*4-5*2+8 =16-16+12-10+8=10. |
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