If `f(x)={{:(,[x]+[-x],,,xne2 ),(," "lamda,,,x=2):}` then `f` is continuous at x=2, provided `lamda` is equal to -A. 1B. 0C. -1D. 2

If `f(x)={{:(,[x]+[-x],,,xne2 ),(," "lamda,,,x=2):}` then `f` is conti

1.	If `f(x)={{:(,[x]+[-x],,,xne2 ),(," "lamda,,,x=2):}` then `f` is continuous at x=2, provided `lamda` is equal to -A. 1B. 0C. -1D. 2
Answer» Correct Answer - B `becausef(x)` is continuous at x = 2 `thereforef(2)=underset(xto2)(lim)f(x)` `rArr lamda=underset(xto2)(lim)[x]+[-x]` `lamda`=-1 `{{:(because" we know "[x]+[-x]=0: x in1),(" "-1:x notin1):} `

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If `f(x)={{:(,[x]+[-x],,,xne2 ),(," "lamda,,,x=2):}` then `f` is continuous at x=2, provided `lamda` is equal to -A. 1B. 0C. -1D. 2

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