1.

If f(x)=⎧⎪⎨⎪⎩x3,x<03x−2,0≤x≤2x2+1,x>2 Then find the value(s) of x for which f(x)=2.

Answer»

If f(x)=x3,x<03x2,0x2x2+1,x>2
Then find the value(s) of x for which f(x)=2.




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