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If f(x)=⎧⎨⎩xksin(1x),x≠00,x=0 is differentiable at x=0, then (where k is an integer) |
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Answer» If f(x)=⎧⎨⎩xksin(1x),x≠00,x=0 is differentiable at x=0, then (where k is an integer) |
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