1.

If f(x+y)=f(x)+f(y)−xy−3 and f(1)=3, then the number of solutions for f(n)=3n, where n∈N is

Answer»

If f(x+y)=f(x)+f(y)xy3 and f(1)=3, then the number of solutions for f(n)=3n, where nN is



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