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If f1(x)=xx−1 and fn(x)=f1(fn−1(x)) for n≥2, then the integral value of x that satisfies f101(x)=3x is |
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Answer» If f1(x)=xx−1 and fn(x)=f1(fn−1(x)) for n≥2, then the integral value of x that satisfies f101(x)=3x is |
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