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If for an ideal gas, the ratio of pressure and volume is constant and is equal to 1 atm `L^(-1)` , the molar heat capacity at constant pressure would beA. `(3)/(2)R`B. `2R`C. `(5)/(2)R`D. zero |
Answer» Correct Answer - C By definition, `H=E+PV` `((dH)/(dT))_(P)=((dE)/(dT))_(P)+P((dV)/(dT))_(p)=C_(p),m` For the given ideal gas, we will have `PV=RT` or `V^(2)=RT` or `2V((dV)/(dT))_(P)=R` or `((dV)/(dT))_(P)=(R)/(2V)` `E=(3RT)/(2)` or `((dE)/(dT))_(P)=(3)/(2)R=C_(v),m` `C_(P),m=(3)/(2)R+Pxx(R)/(2V)=((3)/(2)+(1)/(2))R=2R` |
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