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If for hydrogen `C_(P) - C_(V) = m` and for nitrogen `C_(P) - C_(V) = n`, where `C_(P)` and `C_(V)` refer to specific heats per unit mass respectively at constant pressure and constant volume, the relation between `m` and `n` is (molecular weight of hydrogen = 2 and molecular weight or nitrogen = 14)A. n = 14mB. n = 7mC. m = 7nD. m = 14m |
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Answer» Correct Answer - A At t = 0 particle is at origin (x = 0) potential energy at origin (x = 0) = 15 J `therefore` total mechanical energy `=K.E+P.E=(1)/(2)xx2(4sqrt(6))^(2)+15=96+15=111J` `because U=-x^(3)+6x^(2)+15` `(du)/(dx)=-3x^(2)+12x` `0=-3x(x-4)` `x=0" and "x=4, " since "F=-(du)/(dx)` therefore force on particle is zero at x = 4 Potential energy at (x = 4) = 47 J By conservation of mechanical energy `M.E=K.E+P.E.implies111=47+K.EimpliesV=8ms^(-1)` |
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