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If for two vectors `vec(A)` and `vec(B)`, sum `(vec(A)+vec(B))` is perpendicular to the difference `(vec(A)-vec(B))`. Find the ratio of their magnitude.A. 1B. 2C. 3D. None of these |
Answer» Correct Answer - A `(vec(A)+vec(B))` is perpendicular to `(vec(A)-vec(B))`. Thus `(vec(A)+vec(B)).(vec(A)-vec(B))=0` or `A^(2)+vec(B).vec(A)-vec(A).vec(B)-B^(2)=0` Because of communative property of dot product `vec(A).vec(B)= vec(B).vec(A)` `:. A^(2)-B^(2)=0 or A= B` Thus the ratio of magnitudes `A//B= 1` |
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