If force (F), velocity (v) and time (T)are taken as fundamental units, the dimension of mass are .....

If force (F), velocity (v) and time (T)are taken as fundamental units,

1.	If force (F), velocity (v) and time (T)are taken as fundamental units, the dimension of mass are .....
Answer» `[FV^(-1)]` `[FVT^(-2)]` `[FV^(-1)T^(-1)]` `[FV^(-1)T]` Solution :`m=kF^(a)V^(b)T^(c) .....(1)` Where K is dimensionless CONSTANT and a, b,CER comparing dimension of both sides, `M^(1)L^(0)T^(0)=[M^(1)L^(1)T^(-2)]^(a)xx[M^(0)L^(1)T^(1)]^(c)` `=M^(a)L^(a)T^(-2a)xxL^(b)T^(-b)xxT^(c)` `M^(1)L^(0)T^(0)=M^(a)L^(a+b)T^(-2b-b+c)` Comparing POWERS of M,L,T `a=1,a+b=0 "" -2a+c=0` `:.1+b=0, "" -2xx1-(-1)+c=0` `:.b=-1 "" :. -2+1+c=0` `:. c=1` `:. m=F^(1)v^(-1)T^(1)` [From equ. (1)]