If \(\frac{2}{X} \)+\(\frac{3}{y} \) = 2 and \(\frac{6}{X} \)+ \(\

1.	If \(\frac{2}{X} \)+\(\frac{3}{y} \) = 2 and \(\frac{6}{X} \)+ \(\frac{18}{y} \)= 9, then the values of x and y respectively are :(a) 3 and 2(b) 2 and 3 (c) 4 and 3 (d) 3 and 4
Answer» (b) 2 and 3 Let \(\frac{1}{X}\) = a, \(\frac{1}{y}\) = b, Then, the given equations reduce to: 2a + 3b = 2 ....…(i) 6a + 18b = 9 ….(ii) Now solve eqn (i) and (ii) to find the values of a and b, and then x and y.

If \(\frac{2}{X} \)+\(\frac{3}{y} \) = 2 and \(\frac{6}{X} \)+ \(\frac{18}{y} \)= 9, then the values of x and y respectively are :(a) 3 and 2(b) 2 and 3 (c) 4 and 3 (d) 3 and 4

Answer»

(b) 2 and 3

Let \(\frac{1}{X}\) = a, \(\frac{1}{y}\) = b, Then, the given equations reduce to:

2a + 3b = 2 ....…(i)

6a + 18b = 9 ….(ii)

Now solve eqn (i) and (ii) to find the values of a and b, and then x and y.