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If \(\frac{kx}{(x+4)(2x-1)}\) = \(\frac{4}{x+4}+\frac{1}{2x-1}\) then k is equal to: (a) 9 (b) 11 (c) 5 (d) 7 |
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Answer» (a) 9 \(\frac{kx}{(x+4)(2x-1)}\) = \(\frac{4}{x+4}+\frac{1}{2x-1}\) kx = 8x – 4 + x + 4 kx = 9x k = 9 |
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