1.

If \(\frac{kx}{(x+4)(2x-1)}\) = \(\frac{4}{x+4}+\frac{1}{2x-1}\) then k is equal to: (a) 9 (b) 11 (c) 5 (d) 7

Answer»

(a) 9

\(\frac{kx}{(x+4)(2x-1)}\) = \(\frac{4}{x+4}+\frac{1}{2x-1}\)

kx = 8x – 4 + x + 4 

kx = 9x 

k = 9



Discussion

No Comment Found