If \(\frac{x^2}{\text{by}+\text{cz}}=\frac{y^2}{\text{cz}+\text{ax}}=\frac{z^2}{\text{ax}+\text{by}}\) = 2 , the value of \(\frac{\text{c}}{\text{2c}+\text{z}}+\frac{b}{\text{2b}+\text{y}}+\frac{a}{\text{2a}+x}\) is(a) 2 (b) 1/2 (c) 4 (d) 1/4

If \(\frac{x^2}{\text{by}+\text{cz}}=\frac{y^2}{\text{cz}+\text{ax}}=

1.	If \(\frac{x^2}{\text{by}+\text{cz}}=\frac{y^2}{\text{cz}+\text{ax}}=\frac{z^2}{\text{ax}+\text{by}}\) = 2 , the value of \(\frac{\text{c}}{\text{2c}+\text{z}}+\frac{b}{\text{2b}+\text{y}}+\frac{a}{\text{2a}+x}\) is(a) 2 (b) 1/2 (c) 4 (d) 1/4
Answer» Correct option is (b) 1/2

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If \(\frac{x^2}{\text{by}+\text{cz}}=\frac{y^2}{\text{cz}+\text{ax}}=\frac{z^2}{\text{ax}+\text{by}}\) = 2 , the value of \(\frac{\text{c}}{\text{2c}+\text{z}}+\frac{b}{\text{2b}+\text{y}}+\frac{a}{\text{2a}+x}\) is(a) 2 (b) 1/2 (c) 4 (d) 1/4

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