1.

If from a packof 52 well shuffled cards,cards are drawn one by one without replacement andthe third card is found to be ACE. What is the probaility that first two cards are not ACES?

Answer»

`260/329`
`376/425`
`161/329`
None of these

Solution :`=((.^(48)C_(2))/(.^(52)C_(2))xx4/50)/((.^(48)C_(2))/(.^(52)C_(2))xx4/50+(.^(48)C_(1).^(4)C_(1))/(.^(52)C_(2))xx3/50+(.^(4)C_(2))/(.^(52)C_(2))xx2/50)`
`=(4.^(48)C_(2))/(4.^(48)C_(2)+12.^(48)C_(1)+12)`


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