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If `G(barg), H(barh)` and `P(barp)` are centroid, orthocenter and circumcenter of a triangle and `xbarp + ybarh + zbarg =0` then `(x, y, z)=`A. 1,1,-2B. 2,1,-3C. 1,3,-4D. 2,3,-5 |
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Answer» Correct Answer - B We know that, orthocentre, centroid and circumcentre of a triangle are collinear and centroid divides orthocentre and circumcentre in the ratio 2 : 1 By using internally division `(2p+1h)/(2+1)=g` `Rightarrow 2p+h-3g=0` But it is given xp+yh+zg=0 `therefore x=2, y=1 and z=-3` |
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