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If g is the gravitational field intensity, K.E of the satellite isA)mgR/2B) mgRC) mgR/4D)2mgR |
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Answer» I will go with option (C) Taking m = mass of satellite M = mass of earth g = gravitational field intensity G = Gravitational constant v = velocity of satellite at height R from surface of the earth, where R = radius of earth here GM= gR^2 Here centripetal force = gravitational pull => (mv^2)/(2R) = (GMm)/(2R)^2 => (1/2 mv^2) /R = (gR^2m)/(4R^2)= mg/4 => KE = mgR/4 |
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