If g on the surface of the earth is 9.8 m//s^(2), find its value at a height of 6400 km. (Radius of the earth = 6400 km)

If g on the surface of the earth is 9.8 m//s^(2), find its value at a

1.	If g on the surface of the earth is 9.8 m//s^(2), find its value at a height of 6400 km. (Radius of the earth = 6400 km)
Answer» SOLUTION :Let g at a height H be `g_(h)` `g_(h) = (g)/((1+(h)/(R))^(2))` `h = 6400 km, R = 6400 km, g = 9.8 m//s^(2)` `g_(h) = (9.8)/((1+(6400)/(6400))^(2)) = (9.8)/((1+1)^(2)) = (9.8)/(4) = 2.45 m//s^(2)`