If .g. on the surface of the earth is 9.8 ms^(-2) , find its value at a depth of 3200km (radius of the earth = 6400 km )D

If .g. on the surface of the earth is 9.8 ms^(-2) , find its value at

1.	If .g. on the surface of the earth is 9.8 ms^(-2) , find its value at a depth of 3200km (radius of the earth = 6400 km )D
Answer» Solution :epth , d= 3200km The EXPRESSION for the ACCELERATION due to gravity at depth .d. is `g_d = G \|1 - d/R\| rArr g_d = 9.8 \|1- 3200/6400\| rArr g_d = 4.9 ms^(-2)`