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If g(x) = e^2x+e^x-1 and h(x) = 3x^2-1 the value of g(h(0)) is |
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Answer» Given that g(x) =e^2x+e^x-1 H(x) =3x^2-1 Now g(h(0))=g(3x^2-1) =g(3(0)-1) =g(-1) =e^2(-1)+e^(-1) - 1 =1/e^2+1le - 1 After lcm =1+e-1 /e^2 =e/e^2 =1/e |
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