If g(x)=limm→∞xmf(1)+h(x)+12xm+3x+3 and h(x) both are continuous a – InterviewSolution

1.	If g(x)=limm→∞xmf(1)+h(x)+12xm+3x+3 and h(x) both are continuous at x=1 and g(1)=limx→1(loge(ex))2logex, then the value of 12g(1)+6f(1)−4h(1) is
Answer» If $g (x) = lim m \to \infty \frac{x^{m} f (1) + h (x) + 1}{2 x^{m} + 3 x + 3}$ and $h (x)$ both are continuous at $x = 1$ and $g (1) = lim x \to 1 ({log}_{e} (e x))^{\frac{2}{{log}_{e} x}}$ , then the value of $12 g (1) + 6 f (1) - 4 h (1)$ is

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