1.

If hati xx [ (veca-hatj) xxhati]+ hatj xx [(veca - hatk)xx hatj] +hatk xx [(veca-hati) xx hatk]=0 and veca=xhati+y hatj+z hatk, then :

Answer»

`x+y=1`
`y+z=(1)/(2)`
`x+z=1`
NONE of these

ANSWER :A::C


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