1.

If heat of formation of HI in the given reactions (i) H_(2)(g) + I_(2) to I_(2)(s) to 2HI (ii) H_(2)(g) +I_(2)(g)to 2HI(g) are 26 KJ and -4.5 "mol"^(-1) + respectively , then the heat of sublimation of iodine is

Answer»

30.5 KJ
61.0 KJ
21.5 KJ
`-30.5 KJ`

Solution :In order to GET enthalpy of SUBLIMATION multiply the heat of FORMATION given for per mole by 2 and then subtract (ii) and (i)

`DeltaH=26xx2-(-4.5xx2)=61.0` KJ


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