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If hydrogen electrode dipped I 2 solution of pH=3 and pH=6 and salt bridge is connected the e.m.f. of resulting cell isA. 0.177VB. 0.3VC. 0.052VD. 0.104V

Answer» Correct Answer - A
`E_(cell)=-0.059log((10^(-6))/(10^(-3)))=-0.059log10^(-3)`
`=0.059xx(-3)=0.177V`.


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