1.

If I_(1)=int_(x)^(1)(1)/(1+t^(2)) dt and I_(2)=int_(1)^(1//x) dt "for" x gt0 then,

Answer»

`I_(1)=I_(2)`
`I_(1)gtI_(2)`
`I_(2)=I_(1)`
none of these

Solution :PUTTING `t=(1)/(u)"in" I_(1)`, we GET
`I_(1)=UNDERSET(1//x)overset(1)int(1)/(1+(1)/(u^(2)))(-(1)/(u^(2)))du=-underset(1//x)overset(1)int(du)/(u^(2)+1)=underset(1)overset(1//x)int du=I_(2)`


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